Calculates the cumulative frequency table from below for a discrete data set in accordance with the open right boundary (ORB) convention.
[Visual Basic]
Overloads Public Shared Function CFrequencyTableBOR( _
ByVal s As Series, _
ByVal boundaries() As Double _
) As Series
[C#]
public static Series CFrequencyTableBOR(
Series s,
double[] boundaries
);
The value of the cumulative frequency table values at a given point is the number of elements within the data set below the highest value of that interval of the frequency table constructed in accordance with the open right boundary convention.
Within this example we work through an illustration in which the cumulative frequency table from below using the open right boundary convention is evaluated.
Consider the set of boundaries { 1, 2, 3, 4, 5 }
, which divide the real
line into six sub-intervals. Now if we use the open right boundary convention then the
real line will be divided into the sub-intervals:
(-infinity, 1), [1, 2), [2, 3), [3, 4), [4, 5), [5, infinity)
Note that, each point on the real line can be assigned to one of these sub-intervals
and therefore when assigning a data point to one of these intervals there will only
be one sub-interval in which it belongs.
Therefore, if we consider the data set { 0.5, 1.4, 1.3, 2.0, 2.3, 4.5, 5.5}
,
if the assign this data set in accordance with the above the conventions then we will
have using Open Right Boundary (ORB) convention:
(-infinity, 1]
, we assign the data element 0.5
;
and hence the frequency of this interval is 1
.
[1, 2)
, we assign the data element 1.4, 1.3
;
and hence the frequency of this interval (wrt ORB convention) is 2
.
[2, 3)
, we assign the data element 2.0, 2.3
;
and hence the frequency of this interval (wrt ORB convention) is 2
.
[3, 4)
, we assign no data elements, and hence the frequency
of this interval (wrt ORB convention) is 0
.
[4, 5)
, we assign the data element 4.5
,
and hence the frequency of this interval (wrt ORB convention) is 1
.
[5, infinity)
, we assign the data element 5.5
,
and hence the frequency of this interval (wrt ORB convention) is 1
.
Now in follows that the associated values of the cumulative frequency table are given by:
1
is: 1
2
is: 3
3
is: 5
4
is: 5
5
is: 6
5
is: 7
Hence, for this case the series returned by this methods to represent the cumulative
frequency table would be: {1, 3, 5, 5, 6, 7}
.
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